2H9863 ANGLE Caterpillar parts D6C ANGLE

Rating:

**Alternative (cross code) number:**

CA2H9863

2H-9863

2H9863

Weight: 0.30 pounds 0 kg.

Buy ANGLE 2H9863 Caterpillar genuine, new aftermarket tractor parts with delivery

TRACK-TYPE TRACTOR,

## Compatible equipment models: 2H9863:

## Information:

Series-Parallel Circuits

Illustration 6 g01070324

A series-parallel circuit is composed of a series section and a parallel section. All of the rules previously discussed regarding series circuits and parallel circuits are applicable in solving for unknown circuit values.Although some series-parallel circuits appear to be very complex, the series parallel circuits are solved quite easily by using a logical approach. The following tips will make solving series-parallel circuits less complicated:

Examine the circuit carefully. Then determine the path or paths that current may flow through the circuit before returning to the source.

Redraw a complex circuit to simplify the appearance.

When you simplify a series parallel circuit, begin at the farthest point from the voltage source. Replace the parallel resistor combinations one step at a time.

A correctly redrawn series parallel (equivalent) circuit will contain only ONE series resistor in the end.

Apply the simple series rules for determining the unknown values.

Return to the original circuit and plug in the known values. Use Ohm's Law to solve the remaining values.Solving a Series-Parallel Problem

Illustration 7 g01070325

The series parallel circuit, as shown in Illustration 7, shows a 2Ohms resistor in series with a parallel branch that contains a 6Ohms resistor and a 3Ohms resistor. To solve this problem it is necessary to determine the equivalent resistance for the parallel branch. Using the following equation, solve for the parallel equivalent (Re) resistance:1/Re = 1/R2 + 1/R31/Re = 1/6 + 1/3 or1/Re = .1666 +.3333 = .50 or1/Re = 1/.50 or Re = 2 ohmsIllustration 7 has been redrawn (See Illustration 8) with the equivalent resistance for the parallel branch. Solve circuit totals by using simple Ohm's Law rules for series circuits.

Illustration 8 g01070328

Using the rules for series circuits, the total circuit resistance can now be calculated by using the equation Rt = R1 + Re or Rt = 2 + 2 or 4 ohms.The remaining value that is unknown is current. Again, using Ohm's Law Circle, current can be calculated by the equation:I = E/R orI = 12/4 orI = 3 ampIllustration 9 shows all the known values.

Illustration 9 g01070330

Circuit calculations indicate that the total current flow in the circuit is 3 amps. Since all current flow that leaves the source must return, you know that the 3 amps must flow through R1. It is now possible to calculate the voltage drop across R1 by using the equation E = I × R, or E = 3A × 2Ohms, or E1 = 6 volts.If 6 volts is consumed by resistor R1, the remaining source voltage (6V) is applied to both parallel branches. Using Ohm's Law for the parallel branch reveals that 1 amp flows through R2 and 2 amps flow through R3 before combining into the total circuit current of 3 amps returning to the negative side of the power source.Other Methods and Tips for Solving Complex Series Parallel Circuits

As stated earlier, complex circuits can be easily solved by carefully examining the path for current flow and then draw the circuit again. No matter how complex a circuit appears, drawing an equivalent circuit

Illustration 6 g01070324

A series-parallel circuit is composed of a series section and a parallel section. All of the rules previously discussed regarding series circuits and parallel circuits are applicable in solving for unknown circuit values.Although some series-parallel circuits appear to be very complex, the series parallel circuits are solved quite easily by using a logical approach. The following tips will make solving series-parallel circuits less complicated:

Examine the circuit carefully. Then determine the path or paths that current may flow through the circuit before returning to the source.

Redraw a complex circuit to simplify the appearance.

When you simplify a series parallel circuit, begin at the farthest point from the voltage source. Replace the parallel resistor combinations one step at a time.

A correctly redrawn series parallel (equivalent) circuit will contain only ONE series resistor in the end.

Apply the simple series rules for determining the unknown values.

Return to the original circuit and plug in the known values. Use Ohm's Law to solve the remaining values.Solving a Series-Parallel Problem

Illustration 7 g01070325

The series parallel circuit, as shown in Illustration 7, shows a 2Ohms resistor in series with a parallel branch that contains a 6Ohms resistor and a 3Ohms resistor. To solve this problem it is necessary to determine the equivalent resistance for the parallel branch. Using the following equation, solve for the parallel equivalent (Re) resistance:1/Re = 1/R2 + 1/R31/Re = 1/6 + 1/3 or1/Re = .1666 +.3333 = .50 or1/Re = 1/.50 or Re = 2 ohmsIllustration 7 has been redrawn (See Illustration 8) with the equivalent resistance for the parallel branch. Solve circuit totals by using simple Ohm's Law rules for series circuits.

Illustration 8 g01070328

Using the rules for series circuits, the total circuit resistance can now be calculated by using the equation Rt = R1 + Re or Rt = 2 + 2 or 4 ohms.The remaining value that is unknown is current. Again, using Ohm's Law Circle, current can be calculated by the equation:I = E/R orI = 12/4 orI = 3 ampIllustration 9 shows all the known values.

Illustration 9 g01070330

Circuit calculations indicate that the total current flow in the circuit is 3 amps. Since all current flow that leaves the source must return, you know that the 3 amps must flow through R1. It is now possible to calculate the voltage drop across R1 by using the equation E = I × R, or E = 3A × 2Ohms, or E1 = 6 volts.If 6 volts is consumed by resistor R1, the remaining source voltage (6V) is applied to both parallel branches. Using Ohm's Law for the parallel branch reveals that 1 amp flows through R2 and 2 amps flow through R3 before combining into the total circuit current of 3 amps returning to the negative side of the power source.Other Methods and Tips for Solving Complex Series Parallel Circuits

As stated earlier, complex circuits can be easily solved by carefully examining the path for current flow and then draw the circuit again. No matter how complex a circuit appears, drawing an equivalent circuit

## Caterpillar parts catalog:

### Parts angle Caterpillar catalog:

3Y4264
ANGLE

D6C

D6C

1V3711
ANGLE ASSEM.

141, 191, D4D

141, 191, D4D

1V3710
ANGLE ASSEM.

141, 191, D4D

141, 191, D4D

9K2994
ANGLE ASSEM.

941, 955K, 955L, D4D

941, 955K, 955L, D4D

6S7726
ANGLE

931

931

6S7725
ANGLE

931

931

6D3367
ANGLE

561C, D5, D6C

561C, D5, D6C