PIN 5E8773 - Caterpillar

Illustration 1 g01262056
Boom Float Solenoid connectionsThis diagnostic code is associated with the Boom Float Solenoid. The FMI 06 means that the Implement Control 2 ECM has determined that the current for the solenoid circuit is above normal. The boom float solenoid is a 24 VDC solenoid that is controlled by a Implement Control 2 ECM ON/OFF driver output. The solenoid is energized by the Implement Control 2 ECM when the Boom Float UP/DOWN mode is selected by the operator on the Soft Switch Panel. This solenoid can be overridden in Cat ET.Conditions that can cause this diagnostic code are listed:
The energize circuit of the solenoid is shorted to a ground source.
The solenoid has failed.
The ECM has failed. This is unlikely. Note: Before performing this procedure, inspect the harness connectors that are involved in the circuit. Poor connections can often be the cause of a problem in an electrical circuit. Verify that all connections in the circuit are clean, secure and in good condition. If a problem with a connection is found, correct the problem and verify that this diagnostic code is active before performing this procedure. Note: The following test procedure may create other diagnostic codes. Ignore these created diagnostic codes and clear these diagnostic codes when the original diagnostic code has been corrected.Test Step 1. CHECK THE SOLENOID
Turn the disconnect switch and the key start switch to the ON position. Do not start the engine.
Observe the status of the diagnostic code.
Disconnect the solenoid with the active diagnostic code from the machine harness. Expected Result:The CID 0370 FMI 06 code changes to a CID 0370 FMI 05 code when the solenoid is disconnected.Results:
YES - The CID 0370 FMI 06 code changes to a CID 0370 FMI 05 code when the solenoid is disconnected. The circuit is correct.Repair: The solenoid has failed. Repeat this test "CHECK THE SOLENOID" in order to verify the solenoid failure. Replace the solenoid.STOP
NO - CID 0370 FMI 06 remains active. Disconnecting the solenoid did not affect the status of the diagnostic code. Proceed to Test Step 2.Test Step 2. CHECK THE ENERGIZE CIRCUIT OF THE SOLENOID FOR A SHORT TO GROUND
Turn the key start switch and the disconnect switch to the OFF position.
The solenoid remains disconnected from the machine harness.
Disconnect the machine harness connectors J1 and J2 from the Implement Control 2 ECM and the Machine Control ECM.
At the Implement Control 2 ECM machine harness connector J2, measure the resistance from the contact J2-6 (wire X784-BR) to frame ground. Measure the resistance from the signal contact J2-6 (wire X784-BR) to all of the other contacts that are used in the Implement ECM 2 connectors and the Machine Control ECM connectors.Expected Result:Each resistance measurement is greater than 5000 ohms.Results:
OK - Each resistance measurement is greater than 5000 ohms. The solenoid circuit is not shorted in the machine harness. Proceed to Test Step 3.
NOT OK - One or more of the resistance measurements is less than 5000 ohms. There is a short in the machine harness. The