ROLLER-SLIDER 8Y6064 - Caterpillar

Illustration 1 g02412937
Schematic of the "Joystick Steering Left" Solenoid connectionsThis diagnostic code is associated with the "Joystick Steering Left" Solenoid. The FMI 06 diagnostic code means that the Implement ECM 2 has determined that the current for the solenoid circuit is above normal. The Left Steering Solenoid and the Right Steering Solenoid are proportional solenoids that are controlled by the Implement ECM 2 PWM driver output. In order to control the solenoids, the Implement ECM 2 will change the current of the PWM signal according to the position of the thumbwheel.Conditions that can cause this diagnostic code are listed below:
The energize circuit of the solenoid is shorted to a ground source.
The solenoid has failed.
The Implement ECM 2 has failed. This situation is unlikely. Before performing this procedure, inspect the harness connectors that are involved in the circuit. Poor connections can often be the cause of a problem in an electrical circuit. Verify that all connections in the circuit are clean, secure and in good condition. If a problem with a connection is found, correct the problem and verify that this diagnostic code is active before performing this procedure. Note: The following test procedure may create other diagnostic codes. Ignore these created diagnostic codes and clear these diagnostic codes when the original diagnostic code has been corrected.Test Step 1. CHECK THE SOLENOID
Turn the disconnect switch and the key start switch to the ON position. Do not start the engine.
Observe the status of the diagnostic code.
Disconnect the solenoid with the active diagnostic code from the machine harness. Expected Result:The active CID 0727 FMI 06 code changes to a CID 0727 FMI 05 code when the solenoid is disconnected.Results:
YES - The active CID 0727 FMI 06 code changes to a CID 0727 FMI 05 code when the solenoid is disconnected. The circuit is correct.Repair: The solenoid has failed. Repeat this test "CHECK THE SOLENOID" in order to verify the solenoid failure. Replace the solenoid.STOP
NO - The CID 0727 FMI 06 remains active. Disconnecting the solenoid did not affect the status of the diagnostic code. Proceed to Test Step 2.Test Step 2. CHECK THE ENERGIZE CIRCUIT OF THE SOLENOID FOR A SHORT TO GROUNDThe solenoid remains disconnected from the machine harness.
Turn the key start switch and the disconnect switch to the OFF position.
Disconnect the machine harness connector from the Implement Control 2 ECM.
At the Implement Control 2 ECM machine harness connector, measure the resistance from the contact 34 (wire L998-OR) to frame ground. Measure the resistance from the signal contact 34 (wire L998-OR) to all contacts that are used in the Implement Control 2 ECM.Expected Result:Each resistance measurement is greater than 5000 ohms.Results:
OK - Each resistance measurement is greater than 5000 ohms. The solenoid circuit is not shorted in the machine harness. Proceed to Test Step 3.
NOT OK - One or more of the resistance measurements is less than 5000 ohms. There is a short in the machine harness. The short is between wire L998-OR and the circuit with the low resistance measurement.