STEP AS 1171855 - Caterpillar

Illustration 1 g02797630
Schematic of the Left Brake SolenoidThis diagnostic code is associated with the solenoid for the left steering brake. The FMI 03 means that the ECM has determined that the voltage of the solenoid circuit is above normal.The possible causes of the diagnostic code are listed:
The solenoid has failed.
The energize circuit of the solenoid is shorted to the +battery circuit.
The ECM has failed. ECM failure is unlikely.Note: The following test procedure may create other diagnostic codes. Ignore these created diagnostic codes and clear these diagnostic codes when the original diagnostic code has been corrected. Ensure that the diagnostic code of CID 0689 FMI 06 is active before performing this procedure.Note: Use the 146-4080 Digital Multimeter for the measurements in this procedure.System Response:The diagnostic code of CID 0689 FMI 06 will be logged in the internal memory of the Power Train ECM.Test Step 1. CHECK THE SOLENOID.
Turn the disconnect switch and the key start switch to the ON position. Do not start the engine.
Disconnect the machine harness from the solenoid.
At the machine harness connector for the solenoid, install a jumper wire from contact 1 to contact 2.
Observe the status of the diagnostic code.Expected Result:The diagnostic code is active. Then, the diagnostic code is not active as the jumper wire is installed and removed. Results:
YES - The circuit is correct. The solenoid has failed.Repair: Repeat this test "CHECK THE SOLENOID" in order to verify that the solenoid has failed. Replace the solenoid.STOP
NO - The diagnostic code remains active. Proceed to test step 2.Test Step 2. CHECK THE SOLENOID CIRCUIT FOR A SHORT TO GROUND.
The machine harness remains disconnected from the solenoid.
Turn the key start switch and the disconnect switch to the OFF position.
Disconnect the J1 and J2 machine harness connector from the ECM.
At the J1 machine harness connector, measure the resistance from the solenoid contact J1-58 to all possible sources of ground. Expected Result:Each resistance measurement should be greater than 5000 ohms.Results:
YES - The machine harness is correct. Proceed to test step 3.
NO - There is a short in the machine harness.Repair: The short is between the wire for the solenoid signal and the circuit with the low resistance measurement. Repair the machine harness or replace the machine harnessSTOPTest Step 3. CHECK IF THE DIAGNOSTIC CODE REMAINS.
Inspect the contacts and clean the contacts of the harness connectors.
Reconnect all harness connectors.
Turn the disconnect switch and the key start switch to the ON position.
Clear all inactive diagnostic codes.
Operate the machine.
Stop the machine and place the parking brake switch in the ON position.
Check if the diagnostic code for the solenoid is active.Expected Result:The diagnostic code is no longer active. Results:
YES - The diagnostic code is no longer active. The diagnostic code does not exist at this time. The initial diagnostic code may have been caused by a poor electrical connection that was corrected when a harness connector was disconnected and reconnectedSTOP
NO - The diagnostic code has not been corrected.Repair: ECM failure is unlikely. Exit this procedure and perform this procedure again. If the