WHEEL AS 4238545 - Caterpillar

Illustration 1 g01646194
Schematic of the "Winch Spool Out" solenoid
The CID 1885 is associated with the winch spool solenoid. The FMI 06 diagnostic code is recorded when the Implement ECM reads the current of the solenoid as being above normal.The possible causes are listed below:
A wire is shorted to ground.
The solenoid has failed.
The ECM has failed. This condition is unlikely.System Response:
A level 2 warning will be generated. The "Winch Spool Out" function will not work but the function is still enabled.Note: The following procedure can create numerous related diagnostic codes. When all harnesses are reconnected, the related diagnostic codes will be shown as being not active. Clear all related diagnostic codes after this procedure is completed.Note: Ensure that the CID 1885 FMI 06 diagnostic code for the solenoid is active. Test Step 1. CHECK THE SOLENOID.
Turn the disconnect switch and the key start switch to the ON position. DO NOT start the engine.
Disconnect the machine harness from the solenoid.
Observe the status of the diagnostic code. Expected Result:The CID 1885 FMI 06 diagnostic code changes to a CID 1885 FMI 05 diagnostic code when the solenoid is disconnected.Results:
YES - The CID 1885 FMI 06 diagnostic code changes to a CID 1885 FMI 05 diagnostic code when the solenoid is disconnected. The circuit is correct.Repair: The solenoid has failed. Repeat this test "CHECK THE SOLENOID" in order to verify the solenoid failure. Replace the solenoid.STOP
NO - The CID 1885 FMI 06 diagnostic code remains active. Proceed to Test Step 2.Test Step 2. CHECK THE SOLENOID CIRCUIT FOR A SHORT TO GROUND.
The machine harness remains disconnected from the solenoid.
Turn the key start switch and the disconnect switch to the OFF position.
Disconnect the J1 and J2 machine harness connector from the ECM.
At the J1 machine harness connector, measure the resistance from the solenoid contact J1-41 wire (J914-PU(Purple)) to all possible sources of ground. Expected Result:Each resistance measurement should be greater than 5000 ohms.Results:
YES - The machine harness is correct. Proceed to test step 3.
NO - There is a short in the machine harness.Repair: The short is between the wire for the solenoid signal and the circuit with the low resistance measurement. Repair the machine harness or replace the machine harness.STOPTest Step 3. CHECK THE STATUS OF THE DIAGNOSTIC CODE
Inspect the harness connectors and clean the contacts of the harness connectors that are in the affected circuit. Check the wires for damage to the insulation that can be caused by excessive heat or chafing.
Perform a 45 N (10 lb) pull test on each of the wires that are associated with the switch circuit.
Reconnect all harness connectors. Make sure that the connectors are fully seated and the clips for each connector are fastened.
Turn the disconnect switch and the key start switch to the ON position.
Determine if the CID 1885 FMI 06 diagnostic code is active. Expected Result:The CID 1885 FMI 06 diagnostic code is not active.Results:
OK - The CID 1885 FMI 06 diagnostic code is not active. The diagnostic code does not exist at this time.